diverse Änderungen, Versuch der Lösung der zweiten GHA mit Louville
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@@ -3,7 +3,7 @@ from numpy import sin, cos, tan
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import winkelumrechnungen as wu
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from ellipsoide import EllipsoidBiaxial
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def gha1(re, x0, y0, z0, A0, s, num):
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def gha1(re: EllipsoidBiaxial, x0, y0, z0, A0, s, num):
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phi0, lamb0, h0 = re.cart2ell(0.001, wu.gms2rad([0, 0, 0.001]), x0, y0, z0)
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f_phi = lambda s, phi, lam, A: cos(A) * re.V(phi) ** 3 / re.c
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